5b^2+28b+19=4

Solution for 5b^2+28b+19=4 equation:

Simplifying
5b2 + 28b + 19 = 4

Reorder the terms:
19 + 28b + 5b2 = 4

Solving
19 + 28b + 5b2 = 4

Solving for variable 'b'.

Reorder the terms:
19 + -4 + 28b + 5b2 = 4 + -4

Combine like terms: 19 + -4 = 15
15 + 28b + 5b2 = 4 + -4

Combine like terms: 4 + -4 = 0
15 + 28b + 5b2 = 0

Factor a trinomial.
(5 + b)(3 + 5b) = 0

Subproblem 1
Set the factor '(5 + b)' equal to zero and attempt to solve:

Simplifying
5 + b = 0

Solving
5 + b = 0

Move all terms containing b to the left, all other terms to the right.

Add '-5' to each side of the equation.
5 + -5 + b = 0 + -5

Combine like terms: 5 + -5 = 0
0 + b = 0 + -5
b = 0 + -5

Combine like terms: 0 + -5 = -5
b = -5

Simplifying
b = -5
Subproblem 2
Set the factor '(3 + 5b)' equal to zero and attempt to solve:

Simplifying
3 + 5b = 0

Solving
3 + 5b = 0

Move all terms containing b to the left, all other terms to the right.

Add '-3' to each side of the equation.
3 + -3 + 5b = 0 + -3

Combine like terms: 3 + -3 = 0
0 + 5b = 0 + -3
5b = 0 + -3

Combine like terms: 0 + -3 = -3
5b = -3

Divide each side by '5'.
b = -0.6

Simplifying
b = -0.6
Solution
b = {-5, -0.6}